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12 April, 03:27

Sulfur dioxide gas reacts with oxygen gas for form sulfur trioxide gas. the equilibrium constant for the reaction at 6000c is 4.34. an equilibrium mixture is found to have [so3] = 0.391 m and [o2] = 0.125 m at 6000c. what is the concentration of sulfur dioxide?

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  1. 12 April, 03:47
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    When the balanced equation for this reaction is:

    2SO3 → 2SO2 + O2 so, by using ICE table:

    initial 0.391 0 0.125m

    change - X + 2X + X

    Equ (0.391-X) 2X 0.125+X

    when Keq = concentration of products / concentration of reactants

    so, by substitution

    4.34 = [2X]^2 * [0.125+X] / [0.391-X]^2 by solving for X

    ∴ X = 0.357 m

    ∴ the concentration of SO2 = 2x = 2 * 0.357

    = 0.714 m
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