The heat released when the temperature of 25 grams of water changes from 75 C to 30 C

Q = - 4702.5 J

Explanation:

Given dа ta:

Mass of water = 25 g

Initial temperature = 75°C

Final temperature = 30°C

Heat released = ?

Solution:

Formula:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 30°C - 75°C

ΔT = - 45°C

Q = m. c. ΔT

Q = 25 g * 4.18 J/g.°C * - 45 °C

Q = - 4702.5 J