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24 February, 18:55

6 Li + N2 - -> 2 Li3N

How much N2 is needed to make 1.34 moles of Li3N?

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  1. 24 February, 19:08
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    Answer: 0.67 moles

    Explanation:

    6 Li (s) + N2 (g) - --> 2 Li3N (s)

    The balanced reaction above shows that 6 moles of Lithium, (Li) added to 1 mole of Nitrogen gas, (N2) yields 2 moles of Lithium nitrite, (Li3N)

    I. e 1 mole of N2 = 2 moles of Li3N

    Since the number of N2 needed to make 1.34 moles of Li3N is unknown, it is represented by Y

    So, 1 mole of N2 = 2 moles of Li3N

    Y = 1.34 moles of Li3N

    To get the value of Y, cross multiply

    1.34 x 1 = Y x 2

    1.34 = 2Y

    To get the value of Y divide both sides by 2

    1.34/2 = 2Y/2

    0.67 = Y

    Thus, 0.67 moles of N2 is needed to make 1.34 moles of Li3N.
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