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29 June, 21:44

How many mg of calcium are present in a 500-mg tablet of calcium carbonate? ?

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  1. 29 June, 21:57
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    The molar mass of calcium carbonate is 100 mg/mmol, so the number of moles is:

    moles CaCO3 = 500 mg / (100 mg/mmol) = 5 mmol

    We see that there is 1 mole of Ca per 1 mole of CaCO3, therefore:

    mass Ca = 5 mmol * (40.08 mg/mmol) = 200.22 mg
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