What is the maximum volume of 0.788M CaCl2 solution that can be prepared using 85.3g CaCl2

Concentration=moles/volume

Volume=moles/concentration

To find the number of moles, you divide the mass of CaCl2 by its molar mass. The molar mass of CaCl2 is: 2x35.45 (molar mass Cl) + 40.08 (molar mass Ca)

Molar mass = 110.98g/mol

Moles=m/molar mass

Moles=85.3/110.98

Moles=0.7686069562

Then you calculate the volume:

Volume = 0.7686069562/0.778

Volume = 0.9879266789L

=0.988L

Therefor the max volume that can be prepared is 0.998L