Ask Question
22 February, 15:10

What mass of ammonium hydroxide is produced when 34 grams of ammonium chloride are added to an excess of potassium hydroxide?

+1
Answers (1)
  1. 22 February, 15:19
    0
    NH4Cl + KOH → NH3 + KCl + H2O

    (34 g NH4Cl) / (53.4917 g NH4Cl/mol) = 0.6356 mol NH4Cl

    (37 g KOH) / (56.10569 g KOH/mol) = 0.6595 mol KOH

    0.6356 mole of NH4Cl would react completely with 0.6356 x (1/1) = 0.6356 mole of KOH, but there is more KOH present than that, so KOH is in excess and NH3Cl is the limiting reactant.

    (0.6356 mol NH4Cl) x (1 mol NH3 / 1 mol NH4Cl) x (17.03056 g NH3/mol) = 11 g NH3
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What mass of ammonium hydroxide is produced when 34 grams of ammonium chloride are added to an excess of potassium hydroxide? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers