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27 August, 19:14

Manganese forms several oxides when combined with oxygen. One of the oxides (Oxide 1) contains 63.2% of Mn and another oxide (Oxide 2) contains 77.5% Mn. You will show that these compounds obey the law of multiple proportions. In the first sample, what is the mass of Manganese per 1 gram of oxygen (O) ? Mass Mn/1go

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  1. 27 August, 19:25
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    Defining law of definite proportions, it states that when two elements form more than one compound, the ratios of the masses of the second element which combine with a fixed mass of the first element will always be ratios of small whole numbers.

    A. One of the oxides (Oxide 1) contains 63.2% of Mn.

    Mass of the oxide = 100g

    Mass of Mn = 63.2 g

    Mass of O = 100 - 63.2

    = 36.8 g

    Ratio of Mn to O = 63.2/36.8

    = 1.72

    Another oxide (Oxide 2) contains 77.5% Mn.

    Mass of oxide = 100 g

    Mass of Mn = 77.5 g

    Mass of O = 100 - 77.5

    = 22.5 g

    Ratio of Mn to O = 77.5/22.5

    = 3.44

    Therefore, the ratio of the masses of Mn and O in Oxide 1 and Oxide 2 is in the ratio 1.72 : 3.44, which is also 1 : 2. So the law of multiple proportions is obeyed.

    B.

    Oxide 1

    Mass of Mn per 1 g of O = mass of Mn/mass of O

    = 77.5/22.5

    = 3.44 g/g of Oxygen.

    Oxide 2

    Mass of Mn per 1 g of O = mass of Mn/mass of O

    = 77.5/22.5

    = 3.44 g/g of Oxygen.
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