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24 February, 17:46

A 50.0-ml volume of 0.15 m hbr is titrated with 0.25 m koh. calculate the ph after the addition of 20.0 ml of koh.

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  1. 24 February, 17:52
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    Given:

    Volume of HBr = 50 ml

    Concentration of HBr = 0.15 m

    Concentration of KOH = 0.25 m

    Volume of KOH = 20 ml

    Balanced Chemical Equation:

    HBr + KOH = = = > KBr + H2O

    pH = log ([acid]/[base]) + pKa

    Ka (HBr) = 1.0 x 10^ 9

    pH = log ([0.15*0.05L]/[0.25*0.020]) - log (1x10^9)

    pH = 9.176
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