A student uses 0.10 M HCl to simulate the acid concentration in the stomach. What volume (in ml) of "stomach acid" reacts with a tablet that contains 0.10 g of magnesium hydroxide?

Given, concentration of HCl = 0.10 M

Mass of Mg (OH) ₂ = 0.10 g

Molar mass of Mg (OH) ₂ = 58.3197 g/mol

Moles = mass / molar mass

Mole of Mg (OH) ₂ = 0.10 g / 58.3197 g/mol

Mole of Mg (OH) ₂ = 1.71

Mg (OH) ₂ (s) + 2HCl (aq) → MgCl₂ (aq) + 2H₂O (l)

According to the balanced equation 1 moles of Mg (OH) ₂ reacts with 2 moles of HCl.

Therefore, 1.71 moles of Mg (OH) ₂ reacts with (2 x 1.71) or 3.42 moles of HCl

Molarity = moles / volume in L

Volume of HCl = 3.42 moles of HCl / 0.10 M HCl

Volume of HCl = 34.2 L or 34200 ml

34200 ml of "stomach acid" reacts with a tablet that contains 0.10 g of magnesium hydroxide.