How many atoms of Phosphorus (symbol P) are in 45.67g of P? (Your answer should just be a number. Do not include atoms as the unit. For scientific notation use the "^" symbol before the exponent. For example 2.54 x 10^5)

Question

Maxim Wagner

Chemistry

8 August, 02:14

How many atoms of Phosphorus (symbol P) are in 45.67g of P? (Your answer should just be a number. Do not include atoms as the unit. For scientific notation use the "^" symbol before the exponent. For example 2.54 x 10^5)

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Answers (2)

Know the Answer?

Sophie Le · Answer 1

8.882 * 10^23

Explanation:

The molar mass of phosphorus is 30.97 g/mol. The moles of P corresponding to 45.67 g are:

45.67 g * (1 mol/30.97 g) = 1.475 mol

In 1 mole of P, there are 6.022 * 10²³ atoms of P (Avogadro's number). The number of atoms of P in 1.475 moles are:

1.475 mol * (6.022 * 10²³ atoms/1 mol) = 8.882 * 10²³ atoms

Arianna Khan · Answer 2

Find the Ar of P, then apply the moles = mass divided by Mr. Then do mr x 45.67 x 6.02 x 10^23 and that should give you the answer.