Glucose (C6H12O6) is an important biological molecule.

(Round the answer to nearest hundredth.)

What is the percent by mass of carbon in glucose?

40.0%.

Explanation:

The molar mass of glucose (C₆H₁₂O₆) = 6 (atomic mass of C) + 12 (atomic mass of H) + 6 (atomic mass of O) = 6 (12.0 g/mol) + 12 (1.0 g/mol) + 6 (16.0 g/mol) = 180 g/mol.

The atomic mass of C in glucose = 6 (atomic mass of C) = 6 (12.0 g/mol) = 72.0 g/mol.

∴ The percent by mass of carbon in glucose = [ (The atomic mass of C in glucose) / (The molar mass of glucose) ] x 100 = [ (72.0 g/mol) / (180 g/mol) ] x 100 = 40.0%.

40% (a)

Explanation:

Option A - 40%, got it right on edge 2020