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8 October, 01:24

A 2 L sample of N2 (g) and a 1 L sample of Ar (g), each originally at 1 atm and 0°C, are combined in a 1 L tank. If the temperature is held constant, what is the total pressure of the gases in the tank? a. 1 atm b. 2 atm c. 3 atm d. 4 atm e. 5 atm

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Answers (2)
  1. 8 October, 01:26
    0
    The total pressure in the tank is 3.0 atm

    Explanation:

    Step 1: Data given

    Volume of the N2 sample = 2.0 L

    Volume of the Ar sample = 1.0 L

    Temperature = 0°C

    Volume of the tank = 1L

    Step 2: Calculate moles of N2

    p*V=n*R*T

    n = (p*V) / (R*T)

    ⇒ with p = the pressure of N2 gas = 1.0 atm

    ⇒ with V = the volume of N2 = 2.0 L

    ⇒ with R = the gas constant = 0.08206 L*atm/K*mol

    ⇒ with T = the temperature = 273.15 K

    n = (1.0*2.0) / (0.08206*273.15)

    n = 0.0892 moles

    Step 3: Calculate moles of Ar

    n = (p*V) / (R*T)

    ⇒ with p = the pressure of Ar gas = 1.0 atm

    ⇒ with V = the volume of Ar = 1.0 L

    ⇒ with R = the gas constant = 0.08206 L*atm/K*mol

    ⇒ with T = the temperature = 273.15 K

    n = (1.0*1.0) / (0.08206*273.15)

    n = 0.0446 moles

    Step 4: Calculate total number of moles

    Tot moles = 0.0892 + 0.0446 = 0.1338 moles

    Step 5: Calculate total pressure

    p*V=n*R*T

    p = (n*R*T) / V

    ⇒ with p = the total pressure = ?

    ⇒ with n = the number of moles = 0.1338 moles

    ⇒ with V = the volume in the tank = 1.0 L

    ⇒ with R = the gas constant = 0.08206 L*atm/K*mol

    ⇒ with T = the temperature = 273.15 K

    p = (0.1338 * 0.08206 * 273.15) / 1

    p = 3.0 atm

    The total pressure in the tank is 3.0 atm
  2. 8 October, 01:35
    0
    c. 3 atm

    Explanation:

    First, we will use the ideal gas equation to find the moles of each gas.

    N₂ (g)

    P * V = n * R * T

    n = P * V / R * T

    n = 1 atm * 2 L / (0.082 atm. L/mol. K) * 273 K

    n = 0.089 mol

    Ar (g)

    P * V = n * R * T

    n = P * V / R * T

    n = 1 atm * 1 L / (0.082 atm. L/mol. K) * 273 K

    n = 0.045 mol

    The total gaseous moles are 0.089 mol + 0.045 mol = 0.134 mol

    Now, we will use the ideal gas equation to find the pressure of the gaseous mixture.

    P * V = n * R * T

    P = n * R * T / V

    P = 0.134 mol * (0.082 atm. L/mol. K) * 273 K / 1 L

    P = 3 atm
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