Ask Question
2 May, 03:07

The following unbalanced equation illustrates the overall reaction by which the body utilizes glucose to produce energy: C6H12O6 (s) + O2 (g) → CO2 (g) + H2O (l) What is the conversion factor that allows for the calculation of moles of carbon dioxide based on moles of glucose?

+3
Answers (1)
  1. 2 May, 03:19
    0
    the conversion factor is f = 6 mol of glucose / mol of CO2

    Explanation:

    First we need to balance the equation:

    C6H12O6 (s) + O2 (g) → CO2 (g) + H2O (l) (unbalanced)

    C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (l) (balanced)

    the conversion factor that allows to calculate the number of moles of CO2 based on moles of glucose is:

    f = stoichiometric coefficient of CO2 in balanced reaction / stoichiometric coefficient of glucose in balanced reaction

    f = 6 moles of CO2 / 1 mol of glucose = 6 mol of glucose / mol of CO2

    f = 6 mol of CO2 / mol of glucose

    for example, for 2 moles of glucose the number of moles of CO2 produced are

    n CO2 = f * n gluc = 6 moles of CO2/mol of glucose * 2 moles of glucose = 12 moles of CO2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The following unbalanced equation illustrates the overall reaction by which the body utilizes glucose to produce energy: C6H12O6 (s) + O2 ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers