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Reilly Mooney
Chemistry
10 October, 13:19
Calculate the ph of the solution 0.2M Mg (OH) 2
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Abbey Howard
10 October, 13:24
0
Mg (OH) 2 is base
Oh = 0.2 x 2 =.4
Poh = - Log (.4)
=.3979
Ph + Poh = 14
Ph = 14 -.3979
= 13.60
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Jadyn Wolfe
10 October, 13:48
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13.60 is the answer
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