Ask Question
1 February, 00:27

Calculate the ph of the solution 0.2M Mg (OH) 2

+1
Answers (2)
  1. 1 February, 00:51
    0
    Mg (OH) 2 is base

    Oh = 0.2 x 2 =.4

    Poh = - Log (.4)

    =.3979

    Ph + Poh = 14

    Ph = 14 -.3979

    = 13.60
  2. 1 February, 01:20
    0
    13.60 is the answer
Know the Answer?