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13 July, 04:21

Determine the empirical formula of a compound found to contain 52.11% carbon, 13.14% hydrogen, and 34.75% oxygen.

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  1. 13 July, 04:30
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    C=52.11/12, H=13.14/1 O=34.75/16, C=4.3425/2.171875 H=13.14/2.171875 O=2.171875/2.171875, C=1.99 H=6 O=1, C=2 H=6 O=1 Empirical Formula=C2H6O
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