Ask Question
24 February, 01:02

Consider water at 1400 kPa and 200 C. What is the specific volume (in m3 / kg) ?

+5
Answers (1)
  1. 24 February, 01:20
    0
    Vw = 2.80907 E-3 m³/Kg

    Explanation:

    specific volume is the inverse of density:

    ⇒ Vw = 1 / ρ

    ∴ water at:

    ⇒ P = 1400 KPa * (1000 Pa / KPa) = 1400000 Pa

    ⇒ T = 200°C = 473 K

    Water at these conditions is found as saturated steam, specific volume would be:

    ⇒ Vw = R*T / P

    ∴ R = 8.3144 Pa. m³ / Kg. K

    ⇒ Vw = ((8.3144) * (473)) / 1400000

    ⇒ Vw = 2.80907 E-3 m³/Kg
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Consider water at 1400 kPa and 200 C. What is the specific volume (in m3 / kg) ? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers