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12 July, 07:04

Calculate the ph of 0.63 m nh3 (kb=1.8*10-5).

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  1. 12 July, 07:28
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    [OH-] = √1.8*10^-5 * 0.15

    [OH-] = 1.64*10^-3M

    pOH = - log (1.64*10^-3)

    pOH = 2.79

    pH = 14 - 2.79

    pH = 11.21
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