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25 January, 11:57

What is the ΔG for the following reaction at 25°C?

SO3 (g) + H2O (l) → H2SO4 (l)

Given:

SO3 (g) : ΔG = - 368 kJper mole

H2O (l) : ΔG = - 237 kJ per mole

H2SO4 (l) : ΔG = - 689.9 kJ per mole

84.9 kJ

558.9 kJ

-84.9 kJ

-558.9 kJ

+2
Answers (1)
  1. 25 January, 12:22
    0
    We write the equation as:

    -368 + - 237 = ΔH + - 689.9

    ΔH = 84.9 kJ/mol

    When written outside of the reaction equation, its sign will be reversed.

    Thus, ΔH = - 84.9 kJ/mol

    The third option is correct.
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