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10 October, 15:23

What is the value of the rate constant for a second order reaction if the reactant conceretation drop sform 0.657 M to 0.0981 M in 17.0 s?

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  1. 10 October, 15:35
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    The rate constant for a second order reaction is

    k = 0.51 dm-3 s-1.

    Explanation:

    In a regular second-order reaction the rate equation is given by v = k[A][B], if the reactant B concentration is constant then v = k[A][B] = k'[A], where k' the pseudo-first-order rate constant = k[B].

    Also 1/|A| = Kt + 1/|Ao|

    But Ao = 0.657 M and

    A = 0.0981 M also

    t = 17.0 s

    Therefore

    1/| 0.0981 M| = K * 17.0 s + 1/| 0.657 M|

    → 10.19/M = 17K + 1.52/M

    10.19/M - 1.52/M = 8.67/M = 17K

    K = 8.67M/17s = 0.51 dm-3 s-1.

    k = 0.51 dm-3 s-1.
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