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29 November, 06:48

Calculate the volume in liters of of a 7.62x10^-6 umol/L Mercury (II) iodide solution that contains 700 mg of mercury (II) iodide (HgI2). Round answer 3 significant figures.

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  1. 29 November, 06:59
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    2.02 * 10⁸ L

    Explanation:

    Moles is denoted by given mass divided by the molecular mass,

    Hence,

    n = w / m

    n = moles,

    w = given mass,

    m = molecular mass.

    From the question,

    w = 700 mg,

    (since, 1 mg = 10 ⁻³ g)

    hence, w = 0.700 g

    m = molecular mass of HgI₂ = 454.4 g/mol.

    Calculating moles by using the above formula,

    n = w / m = 0.700 g / 454.4 g/mol = 1.54 * 10⁻³ mol.

    From the question,

    7.62 x 10⁻⁶ umol/L = 7.62 * 10⁻¹² mol / L

    Since, 1 umol = 10 ⁻⁶ mol

    The Volume in terms of liters is -

    volume = 1 L * 1.54 * 10⁻³ mol / 7.62 * 10⁻¹² mol / L = 2.02 * 10⁸ L
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