A mixture of three gases has a pressure at 298 K of 1380 mm Hg. The mixture is analysed and is found to contain 1.27 mol CO2, 3.04 mol CO, and 1.50 mol Ar. What is the partial pressure of Ar?

Question

Stella Mueller

Chemistry

1 February, 20:10

A mixture of three gases has a pressure at 298 K of 1380 mm Hg. The mixture is analysed and is found to contain 1.27 mol CO2, 3.04 mol CO, and 1.50 mol Ar. What is the partial pressure of Ar?

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Answers (1)

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Ruth Nash · Answer 1

The partial pressure of Ar is 356.3 mmHg

Explanation:

The concept of the molar fraction can be applied to calculate the partial pressure of a gas, in a mixture where the molar fraction is equal to the gas pressure, over the total pressure.

PCO2 / Total pressure = n° moles CO2 / Total moles

So we have the total pressure, the moles of Ar and the total moles

The sum of moles is moles Ar + moles CO + moles CO₂ =

1.27 + 3.04 + 1.5 = 5.81

1,5 moles of Ar / 5.81 moles = Partial pressure Ar / Total Pressure

1,5 moles of Ar / 5.81 moles = Partial pressure Ar / 1380mmHg

(1,5 moles of Ar / 5.81 moles). 1380mmHg = Partial Pressure Ar

356,3 mmHg = Partial Pressure Ar