A student placed 13.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100. mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 55.0 mL sample of this glucose solution was diluted to 0.500 L. How many grams of glucose are in 100. mL of the final solution?

Question

Amir King

Chemistry

15 October, 23:25

A student placed 13.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100. mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 55.0 mL sample of this glucose solution was diluted to 0.500 L. How many grams of glucose are in 100. mL of the final solution?

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Cherokee · Answer 1

Molar mass of glucose = 180 g/mol

moles = mass / molar mass.

hence moles of glucose added = 13.5 g / (180 g/mol) = X mol

those moles in 100.0 mL of solution.

Hence moles in 55.0 mL = (X mol x 55.0 mL) / 100.0 mL

that 55.0 mL was diluted to 0.500 L (500 mL)

Hence glucose moles in 500 mL = moles in 55.0 mL

= (X mol x 55.0 mL) / 100.0 mL

Final 100.0 mL was taken from the diluted solution.

Hence moles in final 100.0 mL = ((X mol x 55.0 mL) / 100.0 mL) x (100.0 mL) / 500.0 mL

= X x 11 / 100

Glucose mass in final 100.0 mL = X x 11 / 100 mol x 180 g/mol

= 1.485 g