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16 November, 23:54

A solution contains 85.0 g of nano3, and has a volume of 750. ml. find the molarity of the solution

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  1. 16 November, 23:58
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    Molarity is defined as the number of moles in 1 L of solution.

    Mass of NaNO₃ present - 85.0 g

    Molar mass of NaNO₃ - 85 g/mol

    The number of NaNO₃ moles - 85.0 g / 85 g/mol = 1 mol

    Volume of solution - 750 mL

    The number of moles in 0.750 mL - 1 mol

    Therefore in 1 L solution, number of NaNO₃ moles - 1/0.75 = 1.33 mol

    Therefore molarity of solution - 1.33 M
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