A certain audio compact disc (cd) contains 783.216 megabytes of digital information. each byte consists of exactly 8 bits. when played, a cd player reads the cd's digital information at a constant rate of 1.4 megabits per second.

Question

Lindsey

Computers & Technology

1 October, 00:04

A certain audio compact disc (cd) contains 783.216 megabytes of digital information. each byte consists of exactly 8 bits. when played, a cd player reads the cd's digital information at a constant rate of 1.4 megabits per second.

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Patience Ferguson · Answer 1

You are not putting the question but I can guess that it asking for the CD duration. To answer this question, you need to convert the CD capacity unit (783.216 megabyte) into megabits which were used for the cd read rate (1.4 megabits/s). The calculation would be:

CD duration: CD capacity / rate = 783.216 megabytes * (8 megabits/megabyte) / (1.4 megabits / s) = 4475.52 second or 74.6 minutes