34. The variable j starts with the value 10. The variable k starts with the value 2. The variable l starts with the value 4. Store the value of j times k in j. Store the value of k times l in l. Add j and l, and store the result in k. Display the value in k on the screen. program

Question

Golden Graham

Computers & Technology

10 September, 10:08

34. The variable j starts with the value 10. The variable k starts with the value 2. The variable l starts with the value 4. Store the value of j times k in j. Store the value of k times l in l. Add j and l, and store the result in k. Display the value in k on the screen. program

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Kendrick Alexander · Answer 1

Following is the program in C+ + language:

#include / / header file

using namespace std; / / namespace

int main () / / main function

{

int j=10; / / initialized j to 10

int k=2; / / initialized k to 2

int i=4; / / initialized i to 4

cout<<"old value of j:"<
j=j*k; //Store the value of k times j in j.

i=k*i; //Store the value of k times i in i.

k=j+i; //add the value of j in i and store in k

cout<<"new value of j:"<
return 0;

}

Output:

old value of j:10

old value of i:4

old value of k:2

new value of j:20

new value of i:8

new value of k:28

Explanation:

Following is the explanation of program:

Declared the variable "j" and initialized 10 to them. Declared the variable "k" and initialized 2 to them. Declared the variable "i" and initialized 4 to them. Print the old value of "j","k" and "i" by using the cout statement. Stored the value of "j" variable in the "k" times of "j" variable. Stored the value of "i" variable in the "k" times of "i" variable. Add the value of "j" variable into "i" variable and store in "k" variable. Finally display the new value of i, j and k variable.