Analyze the following code. Line 1: Integer[] intArray = {1, 2, 3}; Line 2: int i = intArray[0] + intArray[1]; Line 3: int j = i + intArray[2]; Line 4: double d = intArray[0]; Group of answer choices

Question

Shannon Hammond

Computers & Technology

6 October, 01:08

Analyze the following code. Line 1: Integer[] intArray = {1, 2, 3}; Line 2: int i = intArray[0] + intArray[1]; Line 3: int j = i + intArray[2]; Line 4: double d = intArray[0]; Group of answer choices

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Answers (1)

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Jordan Freeman · Answer 1

Line 1 shows array of integers. Line 2 calculates one integer from array values. Line 3 calculates integer from value of line 2 and one value from array. Line 4 shows double value of array instance.

Explanation:

Line 1: In this line we have a declaration of 3 integer values in a form of an array.

Line 2: This line declares variable i which will sum first value of array and second value. In arrays we are starting count from 0 not from 1. Which means that intArray[0] will be 1 and intArray[1] will be 2. When we sum those two int i will be 3.

Line 3: This line declares int j and it sums up result from Line 2 and object from array at second position which is 3 (start counting from 0 as explained before). int j will be 6.

Line 4: This line declares variable d as double. Value of d will be first element of array which is 1. Output will be displayed as 1.0 because double is declaration for decimal numbers.