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28 July, 10:22

Working on this program in Python 3.7:A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:1) The year must be divisible by 42) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is 1712, the output is:1712 is a leap year. Ex: If the input is 1913, the output is:1913 is not a leap year. Your program must define and call the function IsLeapYear (userYear). The function should return true if the input year is a leap year and false otherwise.

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  1. 28 July, 10:45
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    This year according to real calendar today is 12 January 2012
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