Ask Question

An internet access provider (IAP) owns two servers. Each server has a 50% chance of being "down" independently of the other. Fortunately, only one server is necessary to allow the IAP to provide service to its customers, i. e., only one server is needed to keep the IAP's system up. Suppose a customer tries to access the internet

+1
Answers (1)
  1. 23 April, 01:50
    0
    Question Continuation

    Suppose a customer tries to access the internet on 8 different occasions, which are sufficiently spaced apart in time, so that we may assume that the states of the system corresponding to these 8 occasions are independent. What is the probability that the customer will only be able to access the internet on 2 out of the 8 occasions?

    Answer:

    0.311

    Explanation:

    Given

    p = success = 2/8 = ¼ - - - Probability that both servers down at any one event

    p + q = 1

    q = failure = 1 - ¼ = ¾ - - - Probability that at most one server down at any one event

    The number of ways that the customer will only be able to access the internet on 2 out of the 8 occasions is solved by applying binomial distribution below;

    (p + q) ^n where n = 8 and r = 2 is

    nCr * p^r * q ^ (n-r)

    This becomes

    8C2 * (¼) ² * (¾) ^6

    = 8! / (6!2!) * 1/16 * 729/4096

    = 0.31146240234375

    = 0.311 - - - approximated
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An internet access provider (IAP) owns two servers. Each server has a 50% chance of being "down" independently of the other. Fortunately, ...” in 📗 Computers & Technology if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers