What will be the final value of EAX in this example? mov eax, 0 mov ecx, 10; outer loop counter L1: mov eax, 3 mov ecx, 5; inner loop counter L2: add eax, 5 loop L2; repeat inner loop loop L1; repeat outer loop

Question

Kyle Hancock

Computers & Technology

21 November, 20:57

What will be the final value of EAX in this example? mov eax, 0 mov ecx, 10; outer loop counter L1: mov eax, 3 mov ecx, 5; inner loop counter L2: add eax, 5 loop L2; repeat inner loop loop L1; repeat outer loop

+5

Answers (1)

Know the Answer?

Taylor Eaton · Answer 1

eax = 28.

Explanation:

The given code in question will not end. The following code is correct version. eax will be 28 in both scenarios.

mov eax, 0; Unnecessary as next instruction changes this

L1: push ecx; This and the pop below solves the problem

mov eax, 3

mov ecx, 5

L2: add eax, 5

loop L2

pop ecx

loop L1; ECX is decremented first