Write a complete C program to run on the MSP432 platform to do the following:

Declare an array of size 3 x 7 of type uint8_t. Use loops to initialize each array element to contain the value of the sum of its indices (e. g., for element arr[2][5], write a value of 7 to arr[2][5], write a value of 7 to arr[1][6], etc.). Use additional loops to go through the array and test each value - if a value is not a multiple of 5, add that value to a cumulative sum and write a zero to the array element. If it is a multiple of 5, leave it untouched. Print the final result as a 16-bit integer value (the sum of the array elements not multiples of 5). Be sure to compile it in CCS to catch any syntax errors.

Question

Alexandria

Computers & Technology

6 September, 09:25

Write a complete C program to run on the MSP432 platform to do the following:

Declare an array of size 3 x 7 of type uint8_t. Use loops to initialize each array element to contain the value of the sum of its indices (e. g., for element arr[2][5], write a value of 7 to arr[2][5], write a value of 7 to arr[1][6], etc.). Use additional loops to go through the array and test each value - if a value is not a multiple of 5, add that value to a cumulative sum and write a zero to the array element. If it is a multiple of 5, leave it untouched. Print the final result as a 16-bit integer value (the sum of the array elements not multiples of 5). Be sure to compile it in CCS to catch any syntax errors.

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Answers (1)

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Grace Hill · Answer 1

The C code is given below with appropriate comments

Explanation:

#include

int main ()

{

//array declaration

int arr[3][7], cumulativeSum = 0;

//initialize the array

for (int i=0; i<3; i++)

{

for (int j=0; j<7; j++)

{

arr[i][j] = i+j;

}

}

//calculate the cumulative sum

for (int i=0; i<3; i++)

{

for (int j=0; j<7; j++)

{

if ((arr[i][j] % 5) ! = 0)

{

cumulativeSum + = arr[i][j];

arr[i][j] = 0;

}

}

}

//display the final array

printf ("The final array is: / n/n");

for (int i=0; i<3; i++)

{

for (int j=0; j<7; j++)

{

printf ("%d ", arr[i][j]);

}

printf ("/n");

}

//display the cumulative sum

printf ("/nCumulative Sum = %d", cumulativeSum);

return 0;

}