The overloaded printString method is defined as follows: public static void printString (String s) { System. out. println (s); } public static void printString (String s, int n) { if (s. length () > n) printString (s. substring (0, n)); else printString (s); } Exactly one of these statements is such that, when executed, it causes the String "Scrum" to be printed to the output window. Which one?

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Natalia Maynard

Computers & Technology

30 March, 08:25

The overloaded printString method is defined as follows: public static void printString (String s) { System. out. println (s); } public static void printString (String s, int n) { if (s. length () > n) printString (s. substring (0, n)); else printString (s); } Exactly one of these statements is such that, when executed, it causes the String "Scrum" to be printed to the output window. Which one?

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Bolton · Answer 1

Complete Question:

The overloaded printString method is defined as follows: public static void printString (String s) { System. out. println (s); } public static void printString (String s, int n) { if (s. length () > n) printString (s. substring (0, n)); else printString (s); } Exactly one of these statements is such that, when executed, it causes the String "Scrum" to be printed to the output window. Which one?

A. printString ("Scrump");

B. printString ("Scrumptious");

C. printString ("Scrumptious", 4);

D. printString ("Scrumptious", 5);

E. printString ("Scrumptious", 6);

Answer:

Option D: printString ("Scrumptious", 5);

Explanation:

The method call printString ("Scrumptious", 5); is to the second overloaded method since it is the one that accepts two parameters.

This method prints the substring from 0 to n, in this call, n = 5 (i. e the indexes 0,1,2,3,4) and these are the letters Scrum that is outputed to the console