What does the following code print?

#include void func (int x, int * yPtr, int * zPtr) { * yPtr + = 3; * zPtr + = 4; x + = 5; } int main () { int a, * bPtr, c; a = 5; bPtr = &a; c = * bPtr; * bPtr + = 2; c + = 3; func (c, bPtr, &c); printf ("%d/n", a + * bPtr + c); return 0; }

a. 32

b. 36

c. 51

d. 30

e. none of above

Question

3 December, 18:02

+2

Answers (1)

Know the Answer?

Branden Pace · Answer 1

a. 32

Explanation:

Form the above code

{ * yPtr + =3;

*zPtr,

c+=3;

func (c, bPTR,&c);

the a=*bPtr c

return value 32 after execution