What is the output of the following program? #include using namespace std; class TestClass { private: int val; void showVal () { cout << val << endl; } public: TestClass (int x) { val = x; } }; int main () { TestClass test (77); test. showVal (); return 0; }

Question

Mylee Church

Computers & Technology

30 September, 17:31

What is the output of the following program? #include using namespace std; class TestClass { private: int val; void showVal () { cout << val << endl; } public: TestClass (int x) { val = x; } }; int main () { TestClass test (77); test. showVal (); return 0; }

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Answers (1)

Know the Answer?

Rodolfo Gilbert · Answer 1

The answer to this question is "The program will not compile."

Explanation:

In the given C+ + programming language program. The program will not compile because in the program we define a class that is "TestClass" in this class we define a private variable and a function that is val and showVal (). In this function, we print the value of val variable. Then we define a parameterized constructor, in this constructor we use the private variable val that holds the constructor parameter value. Then we define a main function, in the main function we create a class object test which is defined wrong.

That's why the answer to this question is "The program will not compile."