Ask Question
13 August, 08:46

Write a function that takes an integer, val, as an argument. The function asks the user to enter a number. If the number is greater than val, the function displays Too high. and returns 1; if the number is less than val, the function displays Too low. and returns - 1; if the number equals val, the function displays Got it! and returns 0. Call the function repeatedly until the user enters the right number.

+3
Answers (2)
  1. 13 August, 08:48
    0
    import java. util.*;

    public class num2 {

    public static void main (String[] args) {

    //Set the Value of the argument

    int val = 5;

    //Call the method

    int returnedNum = testInteger (val);

    //Use a While to continously call the method as long as the returned value is not 0

    while (returnedNum! = 0) {

    int rt = testInteger (val);

    //Break out of loop when the user enters correct value and the return is 0

    if (rt = = 0) {

    break;

    }

    }

    }

    //The Method definition

    public static int testInteger (int val) {

    //Prompt and receive user input

    System. out. println ("Enter a number");

    Scanner in = new Scanner (System. in);

    int userNum = in. nextInt ();

    //Check different values using if and else statements

    if (userNum > val) {

    System. out. println ("Too High");

    return 1;

    }

    else if (userNum < val) {

    System. out. println ("Too Low");

    return - 1;

    }

    else{

    System. out. println ("Got it");

    return 0;

    }

    }

    }

    Explanation:

    This is solved with Java Programing Language

    Pay close attention to the comments provided in the code

    The logic is using a while loop to countinually prompt the user to enter a new number as long as the number entered by the user is not equal to the value of the argument already set to 5.
  2. 13 August, 09:14
    0
    def high_low (val):

    number = int (input ("Enter a number: "))

    if number > val:

    print ("Too high")

    return 1

    elif number < val:

    print ("Too low")

    return - 1

    elif number = = val:

    print ("Got it!")

    return 0

    val = 7

    while True:

    if high_low (val) = = 0:

    break

    Explanation:

    The code is in Python.

    Create a function called high_low that takes one parameter, var

    Ask the user for a number. Check the number. If the number is greater than 1, smaller than 1 or equal to 1. Depending on the number, print the required output and return the value.

    Set the value to a number. Create a while loop iterates until the user enters the correct number, when the return value of the function is equal to 0, that means the user entered the correct number. Otherwise, it keeps asking the number and prints the appropriate message.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Write a function that takes an integer, val, as an argument. The function asks the user to enter a number. If the number is greater than ...” in 📗 Computers & Technology if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers