What is the output of the following code segment?

n = 1;

for (; n < = 5; )

cout << n << ' ';

n++;

1. 1 2 3 4 5

2. 1 1 1 ... and on forever

3. 2 3 4 5 6

4. 1 2 3 4

5. 2 3 4 5

Answer

1 2 3 4 5

Explanation:

initialize the value of n with 1

then, for loop is executed until the condition is true.

so, it check the condition 1<=5, condition true, code is executed and print 1

and n become 2.

again check condition 2<=5 condition true, code is executed and print 2

and n become 3.

and so on ...

it print 1 2 3 4 5 after that check condition 6<=5 condition false, it terminate from loop.

Therefore, the answer is 1 2 3 4 5