Write a program that reads a list of integers, and outputs those integers in reverse. The input begins with an integer indicating the number of integers that follow. For coding simplicity, follow each output integer by a space, including the last one. Assume that the list will always contain less than 20 integers.

The program to this question as follows:

Program:

#include / /header file.

int main () / /main method.

{

const int size = 20; / /define variable.

int a[size]; / /define array

int i, n; / /define variable

printf ("Enter number of elements : "); / /message.

scanf ("%d", &n); //input size of array.

printf ("Enter array elements : "); / /message

for (i = 0; i < n; + +i) / /loop

{

scanf ("%d",&a[i]); / /input array elements by user.

}

printf ("Reverse order : /n");

for (i = 0; i < n; + +i) / /loop

{

printf ("%d ", a[n-i-1]); / /print elements in reverse order.

}

return 0;

}

Output:

Enter number of elements : 5

Enter array elements : 5

4

3

2

1

Reverse order:

1 2 3 4 5

Explanation:

The description of the above program as follows:

In the program firstly we include the header file and define a method that is "main method" in the method we define variables that are "size, n, i, and a[]". The size variable is used to make a variable constant that means its value will not change in the program. We pass the size variable value to the array and use i variable for loop. We use variable n and a[] for user inputs. In n variable, we input a number of elements to be inserted into an array and a[] we insert all array elements to insert these elements we use for loop. Then we define another for loop in this loop we print all array elements in reverse order.