You need a 65% alcohol solution. On hand, you have a 450

mL of a 40% alcohol mixture. You also have 95% alcohol

mixture. How much of the 95% mixture will you need to

add to obtain the desired solution?

Question

Samara Maynard

Computers & Technology

17 May, 18:03

You need a 65% alcohol solution. On hand, you have a 450

mL of a 40% alcohol mixture. You also have 95% alcohol

mixture. How much of the 95% mixture will you need to

add to obtain the desired solution?

+4

Answers (1)

Know the Answer?

Hayden Baxter · Answer 1

375 ml of 95% is what we need to obtain the desired solution

Explanation:

Solution

Now

450 ml of 40% alcohol mixture + 95% mix of x = 65% (450 + x)

Thus

0.40 * 450 + 0.95 x = 0.65 (450 + x)

180 + 0.95 x = 0.65 (450 + x)

180 + 0.95 x = 292.5 + 0.65 x

So,

0.95 x - 0.65 x = 292.5 - 180

= 0.3 x = 112.5

x = 112.5/0.3

x = 375 ml

Therefore, we will need 375 ml of 95% solution

You need a 65% alcohol solution. On hand, you have a 450mL of a 40% alcohol mixture. You also have 95% alcoholmixture. How much of the 95% mixture will you need toadd to obtain the desired solution?

You need a 65% alcohol solution. On hand, you have a 450

mL of a 40% alcohol mixture. You also have 95% alcohol

mixture. How much of the 95% mixture will you need to

add to obtain the desired solution?