What is the result of the following code? double[] values = new double[4]; double sum = 0.0; for (int i = 1; i < = 4; i++) { sum + = values[i]; }System. out. println (sum);

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Computers & Technology

5 August, 08:01

What is the result of the following code? double[] values = new double[4]; double sum = 0.0; for (int i = 1; i < = 4; i++) { sum + = values[i]; }System. out. println (sum);

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Answers (1)

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Syllable · Answer 1

The following code as it is results in an array out of bound exception.

Explanation:

The reason for this exception is that you tried to access index 4 for an array of length four, because Arrays are indexed from zero, the last element in an array of length 4, will be at index 3 (i. e. 0,1,2,3)

To fix this change for (int i = 1; i < = 4; i++) to for (int i = 0; i < 4; i++).

In this way you code compiles and returns the sum of all elements in the array. Since this array is only created and empty, it outputs 0.0