Is there a syntax error in the following code? bool hourlyWorker = true; if (hourlyWorker) cout << "The employee is an hourly worker./n"; else cout << "The employee is not an hourly worker./n";

Question

Maci Sloan

Computers & Technology

1 October, 11:28

Is there a syntax error in the following code? bool hourlyWorker = true; if (hourlyWorker) cout << "The employee is an hourly worker./n"; else cout << "The employee is not an hourly worker./n";

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Answers (1)

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Belen · Answer 1

No, there is not

Explanation:

The code will print - > The employee is an hourly worker.

Here is how:

- hourlyWorker is set as true

- Then we check this part of the code - > if (hourlyWorker)

- If this is true, then the code will print "The employee is an hourly worker."

- If not, then the code will print "The employee is not an hourly worker."

Since if (hourlyWorker) is true, it will print "The employee is an hourly worker."