Write the definition of a function reverse, whose first parameter is an array of integers and whose second parameter is the number of elements in the array. The function reverses the elements of the array. The function does not return a value. So far I have this and it's telling me that I am not reversing all the elements. I think it might be an offset issue. My code so far:void reverse (int a[], int x) {int swap; for (int i=0; i<=x; i++) {swap = a[i]; a[i] = a[x]; a[x] = swap; }return; }

Question

Erika Wilson

Computers & Technology

18 May, 19:50

Write the definition of a function reverse, whose first parameter is an array of integers and whose second parameter is the number of elements in the array. The function reverses the elements of the array. The function does not return a value. So far I have this and it's telling me that I am not reversing all the elements. I think it might be an offset issue. My code so far:void reverse (int a[], int x) {int swap; for (int i=0; i<=x; i++) {swap = a[i]; a[i] = a[x]; a[x] = swap; }return; }

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Answers (1)

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Malakai · Answer 1

To reverse the elements in an array, the codes can be written as follows:

void reverse (int a[], int x)

{

int swap;

for (int i = 0; i < x/2; i++)

{

swap = a[i];

a[i] = a[x - i - 1];

a[x - i - 1] = swap;

}

}

Explanation:

There are two aspects that are worth for our concern:

First, in the for-loop, the condition should be set as "x / 2". In every iteration, there are two numbers in the array being swapped.

a[0] swapped with a[x-1] a[1] swapped with a[x - 2] a[2] swapped with a[x - 3] ...

All the elements in the array shall complete swapping when it reaches its middle index.

Second, to ensure we always take the element from the last and followed with the second last, third last etc in next round of iteration, we need to formulate the index as "x - i - 1"