A network address is 131.247.160.0/19. The 19 implies that

A. There are 19 IP addresses available on the network

B. 19 bits are reserved for the host part of IP addresses on the network

C. There are 19 subnets in the network

D. 19 bits are reserved for the network part of IP addresses on the network

Question

Jeremiah Whitney

Computers & Technology

11 August, 04:29

A network address is 131.247.160.0/19. The 19 implies that

A. There are 19 IP addresses available on the network

B. 19 bits are reserved for the host part of IP addresses on the network

C. There are 19 subnets in the network

D. 19 bits are reserved for the network part of IP addresses on the network

+4

Answers (1)

Know the Answer?

Keshawn Horton · Answer 1

D. 19 bits are reserved for the network part of IP addresses on the Network

Explanation:

The / 19, expresses in the CIDR (Classless Interdomain Routing) notation, how many bits are part of the address mask, which represent the network ID in the IPv4 address.

In this case, we have the first 19 bits set to "1", which in decimal notation should be written as follows:

255.255.224.0

A network address is 131.247.160.0/19. The 19 implies thatA. There are 19 IP addresses available on the networkB. 19 bits are reserved for the host part of IP addresses on the networkC. There are 19 subnets in the networkD. 19 bits are reserved for the network part of IP addresses on the network