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Consider the following algorithm. x â 1 for i is in {1, 2, 3, 4} do for j is in {1, 2, 3} do x â x + x for k is in {1, 2, 3, 4, 5} do x â x + 1 x â x + 5 Count the number of + operations done by this algorithm.

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  1. Today, 00:10
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    Number of + operation done by this algorithm is 60

    Explanation:

    i = 4

    j = 3

    k = 6

    Now, let "n" be number of '+' operations

    n = i * j + i * 2k

    substituting the figures

    n = 4 * 3 + 4 * (2 * 6)

    n = 12 + 4 * 12

    n = 12 + 48

    n = 60
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