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Write a loop that reads positive integers from standard input and that terminates when it reads an integers that is not positive. After the loop terminates, it prints out separate by a space on a single line

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  1. 14 March, 02:47
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    I found this loop. But it ends like this: After the loop terminates, it prints out the sum of all the even integers read. Declare any variables that are needed.

    int sum=0;

    int num=1;

    while (num > 0) {

    cin >> num;

    if ((num % 2) = = 0 & (num>0)) {

    sum+=num;

    }

    }

    cout << sum;

    I'm not familiar with coding but I think you can work on this loop and edit it according to your requirement.
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