Consider the following program where the zu format specifier is used to display as an integer the result of sizeof. #include #include typedef union { int * i1; int * i2; }U; int main () { U temp; int i = 50; temp. i1 = &i; printf ("%zu and %d/n", sizeof (temp), * (temp. i2)); return 0; } What is the output of the program above? Note in the choices below indicates output that isn't any of the literal values in the code above.

Question

Sue

Computers & Technology

5 January, 10:46

Consider the following program where the zu format specifier is used to display as an integer the result of sizeof. #include #include typedef union { int * i1; int * i2; }U; int main () { U temp; int i = 50; temp. i1 = &i; printf ("%zu and %d/n", sizeof (temp), * (temp. i2)); return 0; } What is the output of the program above? Note in the choices below indicates output that isn't any of the literal values in the code above.

+3

Answers (1)

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Monster · Answer 1

4 and 50

Explanation:

To answer the question above, we are to first of all consider the size of union will be the max size of datatype in union data. I. E.

sizeof (int * ) is 4 bytes

so, sizeof (U) = sizeof (temp) is 4

and we saved 50 in temp. i1. so, 50 we can access 50 from temp. i2 as well

so, output is 4 and 50