In Java:

Write code to print the location of any alphabetic character in the 2-character string passCode. Each alphabetic character detected should print a separate statement followed by a newline. Ex: If passCode is "9a", output is:Alphabetic at 1import java. util. Scanner; public class FindAlpha {public static void main (String [] args) {Scanner scnr = new Scanner (System. in); String passCode; passCode = scnr. next (); /*Your solution goes here * / }}

The code to this question can be given as:

Code:

//define code.

//conditional statements.

if (Character. isLetter (passCode. charAt (0))) / /if block

{

System. out. println ("Alphabetic at 0"); / /print message.

}

if (Character. isLetter (passCode. charAt (1))) / /if block

{

System. out. println ("Alphabetic at 1"); / /print message.

}

Explanation:

In this code, we define conditional statement and we use two if blocks. In both if blocks we use isLetter () function and charAt () function. The isLetter () function checks the inserted value is letter or not inside this function we use charAt () function that checks inserted value index 1 and 2 is the character or not.

In first if block we pass the user input value and check the condition that if the inserted value is a character and its index is 0 so, it will print Alphabetic at 0. In second if block we pass the user input value and check the condition that if the inserted value is a character and its index is 1 so, it will print Alphabetic at 1.