Consider two hosts, A and B, connected by a single link of rate R bps. Suppose thatthe two hosts are separated by m meters, and suppose the propagation speed along thelink is s meters/sec. Host A is to send a packet of size L bits to Host B. (a) Express the propagation delay, dprop, in terms of m and s. (b) Determine the transmission time of the packet, dtrans, in terms of L and R. (c) Ignoring processing and queueing delays, obtain an expression for the end-to-end delay. (d) Suppose Host A begins to transmit the packet at time t = 0. At time t = dtrans, where is the last bit of the packet? (e) Suppose dprop is greater than dtrans. At time t = dtrans, where is the first bit of the packet? (f) Suppose dprop is less than dtrans. At time t = dtrans, where is the first bit of the packet? (g) Suppose s = 2.5*108, L = 100 bits, and R = 28 kbps. Find the distance m so that d (prop) equals d (trans).

Question

Leonardo Nelson

Computers & Technology

22 August, 21:52

Consider two hosts, A and B, connected by a single link of rate R bps. Suppose thatthe two hosts are separated by m meters, and suppose the propagation speed along thelink is s meters/sec. Host A is to send a packet of size L bits to Host B. (a) Express the propagation delay, dprop, in terms of m and s. (b) Determine the transmission time of the packet, dtrans, in terms of L and R. (c) Ignoring processing and queueing delays, obtain an expression for the end-to-end delay. (d) Suppose Host A begins to transmit the packet at time t = 0. At time t = dtrans, where is the last bit of the packet? (e) Suppose dprop is greater than dtrans. At time t = dtrans, where is the first bit of the packet? (f) Suppose dprop is less than dtrans. At time t = dtrans, where is the first bit of the packet? (g) Suppose s = 2.5*108, L = 100 bits, and R = 28 kbps. Find the distance m so that d (prop) equals d (trans).

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Shayla · Answer 1

A) d (prop) = m / s

(B) d (trans) = L / R

C) certain delays are overlooked, so, d (total) = amount of the illustration above.

D (total) = (mR+Ls) / Rs D) The bit only exits Host A.

E) The bit has been in the link and hasn't arrived until Host B.

F) Host B has received the bit.

G) m = L / R s = 536 km = 120/56x 10 ^ 3 x (2.5x 10 ^ 8)