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You have a network with a subnet of 172.16.17.0/22. Which of the following is a valid host address? A. 172.16.17.1 255.255.255.252B. 172.16.0.1 255.255.240.0C. 172.16.20.1 255.255.254.0D. 172.16.16.1 255.255.255.240E. 172.16.18.255 255.255.252.0F. 172.16.0.1 255.255.255.0

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  1. 8 March, 17:15
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    E. 172.16.18.255 255.255.252.0

    Explanation:

    Oh goodie, this is my home turf.

    The answer is E) 172.16.18.255 255.255.252.0

    This is because your subnet network ID includes mask / 22, which means the ending with 255 255.255.252.0, which is standard for Class B. Only option E falls as an adequate host due to the network being 172.16.16 and broadcasting 16.19.
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