Internet service providers (isp) need to resolve customer problems as quickly as possible. for one isp, past data indicates that the likelihood is 0.80 that customer calls regarding internet service interruptions are resolved within one hour. out of the next 10 customer calls about interrupted service, what is the probability that exactly 7 will be resolved within one hour?

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Princess

Computers & Technology

Today, 13:26

Internet service providers (isp) need to resolve customer problems as quickly as possible. for one isp, past data indicates that the likelihood is 0.80 that customer calls regarding internet service interruptions are resolved within one hour. out of the next 10 customer calls about interrupted service, what is the probability that exactly 7 will be resolved within one hour?

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Loki · Answer 1

I think that the likelihood will still be 0.8 as that means that 8 out of 10 calls will be resolved within one hour so the 7 out of 10 falls within that likelihood so therefore the callers can go by that assumption and be fairly confident that they have quite a high likelihood of having their problems resolved within one hour.

Zachery · Answer 2

To solve this problem, we make use of the binomial probability formula. That is:

P = [n! / (n - r) ! r!] p^r * q^ (n - r)

where,

n is the total number of customer calls = 10

r is the number of resolved customer calls = 7

p is the probability of resolving in one hour = 0.80

q is 1 - p = 0.20

Therefore,

P = [10! / (10 - 7) ! 7!] 0.80^7 * 0.20^ (10 - 7)

P = 0.2013 = 20.13%