Analyze the following code:

public class Test {

public static void main (String[] args) {

A a = new A ();

a. print ();

}

}

class A {

String s;

A (String newS) {

s = newS;

}

void print () {

System. out. println (s);

}

}

Question

Blake Zuniga

Computers & Technology

29 September, 03:34

Analyze the following code:

public class Test {

public static void main (String[] args) {

A a = new A ();

a. print ();

}

}

class A {

String s;

A (String newS) {

s = newS;

}

void print () {

System. out. println (s);

}

}

+2

Answers (1)

Know the Answer?

Karma Steele · Answer 1

Constructor issue

Explanation:

When you look at the Class A, the constructor takes one argument as a parameter, a String.

A (String newS) {

s = newS;

}

However, in the main, the constructor does not take any argument as a parameter.

A a = new A ();

That's why the code does not compile.

Analyze the following code:public class Test {public static void main (String[] args) {A a = new A ();a. print ();}}class A {String s;A (String newS) {s = newS;}void print () {System. out. println (s);}}

Analyze the following code:

public class Test {

public static void main (String[] args) {

A a = new A ();

a. print ();

}

}

class A {

String s;

A (String newS) {

s = newS;

}

void print () {

System. out. println (s);

}

}