Suppose we have a byte-addressable computer using fully associative mapping with 16-bit main memory addresses and 32 blocks of cache. If each block contains 16 bytes. What is the size of the tag field?

Question

Summer Park

Computers & Technology

28 April, 23:55

Suppose we have a byte-addressable computer using fully associative mapping with 16-bit main memory addresses and 32 blocks of cache. If each block contains 16 bytes. What is the size of the tag field?

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Answers (1)

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Damari Davila · Answer 1

Tag field = 12

Explanation:

The computer system is a digital system that communicates with electronics or bits of data. Each components in the device also communicate with one another using bits.

The microprocessor is the computing center. of the system. It has a cache memory which retrieves and holds data for the CPU to executes faster. Which block of the cache is tag with a given size of information.

Tag field = length of address - offset bit - block address bit

= 16 - 4 = 12